Suppose that the speed of sound in air at a given temperature is 400 m/sec. An engine blows a whistle at 1200 Hz frequency. It is approaching an observer at the speed of 1oo m/sec. What is the apparent frequency as heard by the observer
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a
600Hz
b
1200 Hz
c
1500Hz
d
1600Hz
answer is D.
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Detailed Solution
When engine is approaching the observern′=vv−vsn =400400−100×1200=1600Hz