Suppose two deuterons must get as close as 10-14 m in order for the nuclear force to overcome the repulsive electrostatic force. The height of the electrostatic barrier is nearest to
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a
0.14 MeV
b
2.3 MeV
c
1.8 MeV
d
0.56 MeV
answer is A.
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Detailed Solution
deutron is having one proton + one neutron so charge of deutron is 1.602×10-19 CBarrier height =14πε0e2reJ=14πε0ereeV =9×109×1.6×10−1910−14eV=1.44×105eV =0.14MeV
Suppose two deuterons must get as close as 10-14 m in order for the nuclear force to overcome the repulsive electrostatic force. The height of the electrostatic barrier is nearest to