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Questions  

Suppose two deuterons must get as close as 10-14 m in order for the nuclear force to overcome the repulsive electrostatic force. The height of the electrostatic barrier is nearest to

a
0.14 MeV
b
2.3 MeV
c
1.8 MeV
d
0.56 MeV

detailed solution

Correct option is A

deutron is having one proton + one neutron so charge of deutron is 1.602×10-19 CBarrier height =14πε0e2reJ=14πε0ereeV =9×109×1.6×10−1910−14eV=1.44×105eV  =0.14MeV

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