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At surface of earth weight of a person is 72 N then his weight at height $\frac{R}{2}$ from surface of earth is ( R = radius of earth)

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28 N

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detailed solution

Correct option is C

Weight of the body at height R, W' = WRR+h2 = WRR+R22 = W(23)2 = 49W = 49×72 = 32 N

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At surface of earth weight of a person is 72 N then his weight at height R2 from surface of earth is ( R = radius of earth)

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At surface of earth weight of a person is 72 N then his weight at height $\frac{R}{2}$ from surface of earth is ( R = radius of earth)