First slide
Surface tension and surface energy
Question

The surface energy of a liquid drop is E. It is sprayed into 1000 equal droplets. Then its surface energy becomes

Moderate
Solution

Final surface energy=1000×4πr2σ

Initial surface energy=E=4πR2σ

 Again, 43πR3=1000×43πr2  or  R=10r

Now, final energy = 1000×4πr2σ=10×4πR2σ=10E

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