The surface energy of a liquid drop is E. It is sprayed into 1000 equal droplets. Then its surface energy becomes

Final surface energy=1000×4πr2σInitial surface energy=E=4πR2σ Again, 43πR3=1000×43πr2  or  R=10rNow, final energy = 1000×4πr2σ=10×4πR2σ=10E