The surface energy of a liquid drop is E. It is sprayed into 1000 equal droplets. Then its surface energy becomes
1000E
100E
E
10E
Final surface energy=1000×4πr2σ
Initial surface energy=E=4πR2σ
Again, 43πR3=1000×43πr2 or R=10r
Now, final energy = 1000×4πr2σ=10×4πR2σ=10E