The surface energy of a liquid drop is E. It is sprayed into 1000 equal droplets. Then its surface energy becomes

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1000E

100E

10E

answer is D.

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Detailed Solution

Final surface energy=1000×4πr2σInitial surface energy=E=4πR2σ Again, 43πR3=1000×43πr2 or R=10rNow, final energy = 1000×4πr2σ=10×4πR2σ=10E

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