First slide

Surface tension and surface energy

Question

The surface energy of liquid film on a ring of area $0.15 m^{2}$ is (Surface tension of liquid $= 5 N m^{- 1})$

Very Easy

A

0.75 J
B

1.5 J
C

2.25 J
D

3.0 J

Solution

$Surface energy = T \times A = 5 \times 2 \times (0 .15) = 1 .5 J$

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