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Q.

The surface tension of a liquid is 5 N/m.  If a thin film of the area 0.02 m2 is formed on a loop, then its surface energy will be

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a

5×102 J

b

2.5×10−2 J

c

2×10−1 J

d

5×10−1 J

answer is C.

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Detailed Solution

W=T×ΔA=5×2×(0.02) (Film has two free surfaces)=2×10−1J
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