First slide

Surface tension

Question

The surface tension of soap solution is $25 \times 10^{- 3} {Nm}^{- 1}$ The excess of pressure inside a soap bubble of diameter 1 cm is

Easy

A

10 Pa
B

20 Pa
C

5 Pa
D

None of the above

Solution

Excess of pressure
$= \frac{4 T}{r} = \frac{4 \times (25 \times 10^{- 3})}{0 \cdot 5 \times 10^{- 2}} = 20 Pa$

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