First slide

Surface tension

Question

The surface tension of a soap solution is 0.02 N/m. The work done in blowing a soap bubble of radius 0 .015m is of the order of

Easy

A

10^-4 J
B

10^-8 J
C

10 ^-9 J
D

10¹²J

Solution

$Work done = T \times ΔA = 0 \cdot 02 \times \{2 \times 4 \times \frac{22}{7} \times (0 \cdot 015)^{2}\} Ite factor 2 is added as there ar € two surfaces in a soap bubble = 10^{- 4} J$

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