On suspending a mass ‘m’ from a spring of force constant ‘K’ frequency of vibration ‘f’ is obtained. If a second spring as shown in the figure, is arranged then frequency will be
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a
f2
b
f2
c
2f
d
f
answer is A.
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Detailed Solution
f=12πKm∝KBoth springs are in parallel So, f′∝2K∝2ff′=2f