Q.
A swimmer crosses a flowing stream of width d to and fro in time t1 .The time taken to cover the same distance up and down the stream ist2 . Then the time the swimmer would take to swim a distance 2 d in still water is
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a
t12/t2
b
t22/t1
c
t1t2
d
(t1+t2)
answer is A.
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Detailed Solution
Let u be the velocity of swimmer and v be the velocity of river flow. Then t1=2du2−v2 and t2=du−v+du+v=2udu2−v2 If t is the time taken by swimmer to swim a distance 2 d still water, then t=2du t2×t=2udu2−v2×2du=4d2u2−v2 From above, t2×t=t12 or t=t12/t2
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