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A swimmer crosses a flowing stream of width W to and fro in time t1. The time taken to cover the same distance up and down the stream is t2. lf t3 is the time the swimmerwould take to swim a distance 2W in still water, then

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a

t12=t2t3

b

t22=t1t3

c

t32=t1t2

d

t3=t1+t2

answer is A.

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Detailed Solution

Let v be the river velocity and u the velocity of swimmer in still water. Thent1=2Wu2−v2t2=Wu+v+Wu−v=2uWu2−v2 and t3=2WuNow we can see that t12=t2t3

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