A system consisting of two blocks of masses m1 and m2 connected by a spring of spring constant K. A force F is applied on m1 along its weight and removed such that m2 is just lifted. Then F is
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a
m2g
b
(m1+m2)g
c
(m1m2)gm1+m2
d
m1g
answer is B.
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Detailed Solution
For m1 : F+m1g=kx0 For m2 : m2 to lift kx=m2g→2 Loss of potential energy of spring= gain of potential energy of blocks12k(x0−x2)=m1g(x0+x) 12k(x0−x)=m1g kx0−kx=2m1g F+m1g−m2g=2m1g F=(m1+m2)g F=(m1+m2)g
A system consisting of two blocks of masses m1 and m2 connected by a spring of spring constant K. A force F is applied on m1 along its weight and removed such that m2 is just lifted. Then F is