A system consists of three masses m1, m2 and m3 connected by a string passing over a pulley P. The mass m1 hangs freely and m2 and m3 are on a rough horizontal table (the coefficient of friction= μ)The pulley is frictionless and of negligible mass. The downward acceleration of mass m1 is (Assume m1=m2=m3=m

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g(1−gμ)9

2gμ3

g(1−2μ)3

g(1−2μ)2

answer is C.

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Detailed Solution

Force of friction on mass m2=μm2g Force of friction on mass m3=μm3g Let α be common acceleration of the system.∴ a=m1g−μm2g−μm3gm1+m2+m3 Here, m1=m2=m3=m Hence, the downward acceleration of mass m1 is g(1−2μ)3

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