A system is given 300 calories of heat and it does 600 joules of work. How much does the internal energy of the system change in this process(J = 4.18 joules/cal)

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654 Joule

156.5 Joule

– 300 Joule

– 528.2 Joule

answer is A.

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Detailed Solution

JΔQ=ΔU+ΔW,ΔU=JΔQ−ΔWΔU=4.18×300−600=654 Joule

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