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Q.

A system is given 300 calories of heat and it does 600 joules of work.  How much does the internal energy of the system change in this process(J = 4.18 joules/cal)

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a

654 Joule

b

156.5 Joule

c

– 300 Joule

d

– 528.2 Joule

answer is A.

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Detailed Solution

JΔQ=ΔU+ΔW,ΔU=JΔQ−ΔWΔU=4.18×300−600=654 Joule
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