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In a system of particles 8 kg mass is subjected to a force of l6 N along +ve x-axis and another 8 kg mass is subjected to a force of 8 N along +ve y-axis. The magnitude of acceleration of centre of mass and the angle made by it with x-axis are given respectively by:

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By Expert Faculty of Sri Chaitanya
a
52ms-2, θ = 45°
b
35 ms-2, θ = tan-1(23)
c
52ms-2, θ = tan-1(12)
d
31 ms-2, θ = tan-13

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detailed solution

Correct option is C

m1x1 = m2x2,a→cm = F→m = 16i^+8j^16 = i^+12j^|a→cm| = 12+(12)2 = 52 m/s2tan θ = 121 ⇒θ =  tan-1(12)


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The velocity of the CM of a system changes from v1 = 4i m/s to v2 = 3j m/s during time t = 2s. If the mass of the system is m: l0 kg, the constant force acting on the system is:

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