First slide

First law of thermodynamics

Question

A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J. Then its internal energy

Moderate

A

Increases by 600 J
B

Decreases by 800 J
C

Increases by 800 J
D

Decreases by 50 J

Solution

$\begin{array}{l} ΔQ = ΔU + ΔW \\ ∵ ΔQ = 200 cal = 200 \times 4 .2 = 840 J and ΔW = 40 J \\ \Rightarrow ΔU = ΔQ - ΔW = 840 - 40 = 800 J \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App