The system shown in figure is in equilibrium. The mass of the container with liquid is M, density of liquid in the container is ρ and the volume of the block is V. If the container is now displaced downwards through a distance x0 and released such that the block remains well inside the liquid, then during subsequent motion,

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time period of SHM of the container will be 2π Mk

time period of SHM of the container will be 2π M + ρVk

amplitude of SHM of the container is x0

amplitude of SHM of the container is 2x0

answer is B.

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Detailed Solution

Here, effective mass of container,Me=Mass of container + Upthrustg =M+ρVgg=M+ρVHence, T=2πMek=2πM+ρVk

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