For the system shown in the figure, $$m1$$$$m2$$$$m3$$$$m4$$. Initially, the system is at rest in equilibrium condition. If the string joining $$m4$$ and ground is cut, then just after the string is cut. Statement I: $$m1$$,$$m2$$,$$m3$$ remain stationary.Statement II: The value of acceleration of all the four blocks can be determined.Statement III: Only $$m4$$ remains stationary.Statement IV: Only $$m4$$ accelerates.Now, choose the correct options.

Question

For the system shown in the figure, $$m1$$>$$m2$$>$$m3$$>$$m4$$. Initially, the system is at rest in equilibrium condition. If the string joining $$m4$$ and ground is cut, then just after the string is cut. Statement I: $$m1$$,$$m2$$,$$m3$$ remain stationary.Statement II: The value of acceleration of all the four blocks can be determined.Statement III: Only $$m4$$ remains stationary.Statement IV: Only $$m4$$ accelerates.Now, choose the correct options.

Infinity Learn · Accepted Answer

Before cutting the string, the tension in string joining $$m4$$ and ground is $$T=m1+m2$$−$$m3$$−$$m4gAnd$$ the spring force in the spring joining $$m3$$ and $$m4$$ is $$T+m4g$$. . As the string is cut, the spring forces do not change instantly, so just after cutting the string the equilibrium of $$m1$$,$$m2$$ and $$m3$$, would be maintained but ma accelerates in upward direction with acceleration given $$bya=m1+m2$$−$$m3$$−$$m4gm4$$

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