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Questions  

The system shown in the figure is released from rest. At the instant when mass M has fallen through a distance h, the velocity of m will be

a
2gh
b
2ghMm
c
2ghM−mm+M
d
2ghM+mm−M

detailed solution

Correct option is C

loss in P.E. = gain in K.E.M−mgh=12M+mv2∴v=2ghM−mm+M

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