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System shown in figure is released from rest. Pulley and spring are mass less and the friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves the contact with ground is (take force constant of the spring K = 40 N/m and g=10m/s2

 

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a
2 m/s
b
2 2 m/s
c
2 m/s
d
4 m/s

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detailed solution

Correct option is B

when  2 kg mass leaves the ground  tension in the string 2g=kx =40x x=0.5 from coservation of energy 12kx2+12Mv2=Mgx where M= 5kg


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