System shown in figure is released from rest. Pulley and spring are mass less and the friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves the contact with ground is (take force constant of the spring K = 40 N/m and g=10m/s2)

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2 m/s

2 2 m/s

2 m/s

4 m/s

answer is B.

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Detailed Solution

when 2 kg mass leaves the ground tension in the string 2g=kx =40x x=0.5 from coservation of energy 12kx2+12Mv2=Mgx where M= 5kg

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