Questions
The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley and strings to be light, the value of the constant force F applied on A is
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Correct option is B
a=v22s=2510=2.5m/s2 For 6kg:−F−2T=6a ……(1) For 2kg:−T−2g=2(2a) ……(2)From (1) and (2), F= 75 NSimilar Questions
For the system shown in figure, the pulleys are light and frictionless. The tension in the string will be
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