First slide

Application of Newtons laws

Question

The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley and strings to be light, the value of the constant force F applied on A is

Moderate

A

50 N
B

75 N
C

100 N
D

96 N

Solution

$a = \frac{v^{2}}{2 s} = \frac{25}{10} = 2.5 m / s^{2}$
$For 6 kg : - F - 2 T = 6 a$ ……(1)
$For 2 kg : - T - 2 g = 2 (2 a)$ ……(2)
From (1) and (2), F= 75 N

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