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A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua=10J. Along the path adc the amount of heat heat absorbed δQ1=50 J and the work obtained δW1=20 J whereas along the path abc the heat absorbed δQ2=36 J. The amount of work along the path abc is

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a

10 J

b

12 J

c

36 J

d

6 J

answer is D.

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Detailed Solution

According to first law of thermodynamics,δQ=δU+δWAlong the path adc Change in internal energy,δU1=δQ1-δW1=50 J-20 J=30 JAlong the path abc Change in internal energy,δU2=δQ2-δW2 δU2=36 J-δW2As change in internal energy is path independent.∴ δU1=δU2 ∴ 30 J=36 J-δW2 δW2=36 J-30 J=6 J

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