First slide

Location of centre on mass for multiple point masses

Question

For the system of two particles co-ordinates of centre of mass are:

Easy

A

(4, 3)
B

$(\frac{4}{3}, 1)$
C

$(\frac{3}{4}, 1)$
D

$(1, \frac{1}{2})$

Solution

4 kg (0, 0)
2 kg (4, 3)
$x_{cm} = \frac{4 (0) + 2 (4)}{4 + 2} = \frac{4}{3}$
$y_{cm} = \frac{4 (0) + 2 (3)}{4 + 2} = 1$

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