Questions
A system undergoes three quasi-static processes sequentially as indicated in the given figure. 1-2 is an isobaric process, 2-3 is a polytropic process with = 4/3 and 3-1 is a process in which PV= constant. P2 = P1 = 4 x 105 N/m2, P3 =1 x 105 N/m2 and V1 = 1 m3.
The heat transfer for the cycle is , the change in internal energy is and the work done is . Then
detailed solution
Correct option is B
For the process 3→1P1V1=P3V3⇒V3=P1V1P3=4×105×11×105=4m3For the process 2→3P2V2γ=P3V3γ⇒V2=P3P21γV3=41434=414m3=2m3For the process 1→2,W12=P1V2−V1=(2−1)4×105JFor the process 2→3,W23=P2V2−P3V3(γ−1)=(42−1×4)×10543−1=12(2−1)×105JFor the process 3→1,W31=−P1V1lnV3V1 =−4×105×1×ln41ΔU=0 ΔQ=ΔU+ΔW1→2→3→1=4×105(2−1)+12×105(2−1)−4×105×1.386≃1.08×105JΔQ=ΔW≃1.08×105JTalk to our academic expert!
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In the given graph, an ideal gas can change its state from A to C by two paths ABC or AC. Taking, the internal energy of gas at ‘A’ is 10 J, mark the CORRECT option(s)
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