At t=0, the lower end of the bar A is just above the upper end of bar B (mass of bar A=3 kg, mass of bar B=113kg). Find time (in sec) when upper end of block A just crosses the lower end of .8. (Assume the system was released at t=0).g=10m/s2
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answer is 2.
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Detailed Solution
Acceleration of A and B=113−3113+3g=1m/s2 Relative acceleration of A and B=2m/s2 Now by using s=ut+12at2;4=0+12(2)(t)2⇒t=2s