First slide

Simple hormonic motion

Question

T_1,T₂ and T₃ the time periods of a given pendulum on the surface of the earth, at a depth ‘h’ in a mine and at an altitude ‘h’ above the earth’s surface respectively, then

Easy

A

T₁ = T₂ = T₃
B

T₂ < T₁ < T₃
C

T₃ > T₂ > T₁
D

T₁ > T₂ > T₃

Solution

$\large {T_1}\, \propto \,\frac{1}{{\sqrt g }} \to earths;\,{T_2} \propto \,\frac{1}{{\sqrt {g\left( {1 - \frac{h}{R}} \right)} }} \to depth'$
$\large {T_3}\, > {T_2} > {T_1}$

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