First slide

Diodes

Question

Take the breakdown voltage of the Zener diode used in the given circuit as 6V. For the input voltage shown in figure below, the time variation of the output voltage is :
(Graphs drawn are schematic and not to scale)

Moderate

A
B
C
D

Solution

During each half cycle, when $V_{i n}$ builds from 0 to 6V, one of the diodes is in reverse biased but not yet reached break down.
So, the diode branch is open and bypasses the $V_{i n}$ , it will follow the input voltage.
Once $V_{i n}$ builds from 6V to 10V, then one Zener achieves breakdown and other in forward bias $(Δ V = 0)$ produces constant voltage.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App