Taking Rydberg’s constant RH=1.097×107m first and second wavelength of Balmer series in hydrogen spectrum is

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2000 Ao, 3000 Ao

1575 Ao, 2960 Ao

6529 Ao, 4280 Ao

6552 Ao, 4863 Ao

answer is D.

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Detailed Solution

1λ=R1n12−1n22. For first wavelength nn1=2,n2=3⇒λ1=6563 Ao. For second wavelength, n1=2,n2=4⇒λ2=4861Ao

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