Taking Rydberg's constant RH=1.097×107/m .First and second wavelength of Balmer series in hydrogen spectrum is

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2000 A0, 3000 A0

1575 A0, 2960 A0

6529 A0, 4280 A0

6563 A0, 4861 A0

answer is D.

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Detailed Solution

1λ=R1n12−1n22. For first wavelength, n1=2, n2=3⇒λ1=6563 A0. For second wavelength, n1=2, n2=4⇒λ2=4861 A0

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