First slide

Fluid statics

Question

A tank with a square base of area 10m² is divided by a vertical partition in the middle. The bottom of the partition has a small hinged door of area 80m². The tank is full of water in one compartment, and an acid (of relative density 1.7). In the other, both to a height of 4.0m. Compute necessary force to keep the door closed.

Moderate

A

174.76N
B

54.88 N
C

162.4N
D

28.88N

Solution

Hydro static thrust on the door = Hydro static pressure x surface area
$\large \therefore F_w=(\rho_wgh)\times A$
$\large =10^3\times 9.8\times 4\times 20\times 10^{-4}=78.4N$
$\large F_a=1700\times 9.8\times 4\times 20\times 10^{-4}=133.28N$
Net thrust on the door = (133.28 - 78.4)N = 54.88N

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