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A telescope has an objective of focal length 50 cm and an eye piece of focal length 5 cm. The least distance of distinct vision is 25 cm. The telescope is focussed for distinct vision on a scale 200 cm away. The separation between the objective and the eye-piece is

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a

75 cm

b

60 cm

c

71 cm

d

74 cm

answer is C.

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Detailed Solution

fo=50cm,fθ=5cm,D=25cm and uo=200cm Separation between the objective and the eye lens is L=uofouo−fo+feDfe+D=200×50(200−50)+5×25(5+25)=71cm

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