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A telescope has an objective of focal length 50 cm and an eye piece of focal length 5 cm. The least distance of distinct vision is 25 cm. The telescope is focussed for distinct vision on a scale 200 crn away. The separation between the objective and the eye-piece is

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a

75 cm

b

60 cm

c

71 cm

d

74 cm

answer is C.

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Detailed Solution

fo=50 cm, fe=5 cm, D=25 cm and uo=200 cm.Separation between the objective and the eye lens isL=uofouo−fo+feDfe+D=200×50200−50+5×255+25=71 cm

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