First slide

Radiation

Question

The temperature of a body is increased by 50%. The amount of radiation emitted by it would be nearly

Moderate

A

50%
B

225%
C

250%
D

400%

Solution

$T^{'} = \frac{3}{2} T; E^{'} = \frac{81}{16} E$
$(\frac{E^{'}}{E} - 1) \times 100 = (\frac{81}{16} - 1) \times 100$
$\frac{81 - 16}{16} \times 100 = 406.25 = 400$

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