The temperature of the cold junction of a thermocouple is 0°C and the temperature of hot junction is T°C. The e.m.f. is e=16T−0.04T2μVThe inversion temperature Ti is
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a
200°C
b
400°C
c
100°C
d
300°C
answer is B.
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Detailed Solution
Given that e =16T−0⋅04T2At temperature of inversion, e = 0∴ 16Ti−0⋅04Ti2=0or Ti=160⋅04=400∘C