First slide

Heat engine

Question

The temperature entropy diagram of a reversible engine . cycle is given in the Fig. Its efficiency is:

Moderate

A

1/ 3
B

2/3
C

1/2
D

1/4

Solution

According to diagram
Heat supplied $Q_{1} = \frac{3}{2} T_{0} S_{0} [Along hypotenuse]$
Heat rejected $Q_{2} = T_{0} S_{0} [Along base]$
Efficiency $η = \frac{W}{Q_{1}} = \frac{Q_{1} - Q_{2}}{Q_{1}} = \frac{\frac{3}{2} T_{0} S_{0} - T_{0} S_{0}}{\frac{3}{2} T_{0} S_{0}} = \frac{1}{3}$

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