Q.

The temperature of equal masses of three different liquids A, B and C are 12°C, 19°C and 28°C, respectively. The temperature when A and B are mixed is 16°C and that when B and C are mixed is 23°C. The temperature when A and C are mixed is

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18.2∘C

22∘C

20.2∘C

25.2∘C

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Heat gain = Heat lost⇒CA(16−12)=CB(19−16)⇒CACB=34and CB(23−19)=CC(28−23)⇒CBCC=54⇒ CACC=1516 …(i)If θ is the temperature when A and C are mixed, thenCA(θ−12)=CC(28−θ)⇒CACC=28−θθ−12 …(ii)On solving Eqs. (i) and (ii), θ=20.2∘C

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