The temperature of equal masses of three different liquids A, B and C are $$12oC$$, $$19oC$$ and $$28oC$$ respectively. The temperature when A and B are mixed is $$16oC$$ and when B and C are mixed is $$23oC$$. The temperature when A and C are mixed is

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Infinity Learn · Accepted Answer

Heat gain $$=$$ heat lost       $$CA(16$$−$$12)=CB(19$$−$$16)$$⇒$$CACC=1516=54and$$ $$CB(23$$−$$19)=CC(28$$−$$23)$$⇒$$CACC=54$$       ⇒$$CACC=1516$$              .............(i)If$$ θ is the temperature when A and C are mixed then,           $$CA($$θ−$$12)=CC(28$$−θ$$)⇒$$CACC=28$$−θθ−$$12$$ …………(ii)On$$ solving equation $$(i) and (ii), θ$$=20.2$$∘C.

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