The temperature of an ideal gas increased from 120 K to 480 K. If at 120 K the root-mean-square velocity of the gas molecules is y, at 480 K it becomes
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
4 v
b
2 v
c
v/2
d
v/4
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Crms=3RTM or Crms∝T ∴ Crms T1=Crms T1×T2/T1=V×(480/120)=2v