The temperature of an ideal is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is ‘V’ , at 480 K it becomes
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a
4V
b
2V
c
V/2
d
V/4
answer is B.
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Detailed Solution
Vrms=3RTM ⇒ Vrms∝T⇒ V1V2=T1T2=120480 obtained after substituting given valueshere R is universal gas constantV=V; T is absolute temperature;M is molecular weight;V1V2=14given V1=V substitute in above equation,VV2=12⇒V2=2V