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The temperature of inside and outside of a refrigerator arc 273 K and 303 K respectively. Assuming that the refrigerator cycle is reversible, for every ioule of work done, the heat delivered to the surrounding will be nearly

a
10 J
b
20 J
c
30 J
d
50 J

detailed solution

Correct option is A

β=Q2W=T2T1−T2Here T2=273 K,T1=303K and W=1JSubstituting the values, we get Q2=9⋅15≈10J

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