First slide

Refrigerator

Question

The temperature of inside and outside of a refrigerator arc 273 K and 303 K respectively. Assuming that the refrigerator cycle is reversible, for every ioule of work done, the heat delivered to the surrounding will be nearly

Moderate

A

10 J
B

20 J
C

30 J
D

50 J

Solution

$Î² = \frac{Q_{2}}{W} = \frac{T_{2}}{T_{1} â T_{2}}$
Here $T_{2} = 273 K, T_{1} = 303 K and W = 1 J$
Substituting the values, we get $Q_{2} = 9 â 15 â 10 J$

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