First slide

Heat engine

Question

The temperature inside and outside a refrigerator are 273 K and 303 K respectively. Assume that the refrigeration cycle is reversible. For every joule of work done the heat delivered to the surrounding will be approximately:

Easy

A

10 joule
B

20 joule
C

30 joule
D

40 joule

Solution

$η = 1 - \frac{T_{2}}{T_{1}} = \frac{W}{Q_{1}} = \frac{W}{Q_{2} + W} \Rightarrow Q_{2} = (\frac{T_{2}}{T_{1}} - 1) W$

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