Questions
The temperature of inside and outside of a refrigerator (working based on carnot cycle) are 273K and 303K respectively. Assuming that the refrigerator cycle is reversible, for every joule of work done, the heat delivered to the surrounding will be nearly :
detailed solution
Correct option is A
GivenTemperature of inside T2=273 KTemperature of outside T1=303 Kk=Q2W=T2T1−T2=27330Heat delivered to surrounding∴Q1=Q2+W=k+1W=9+1 J=10 JTalk to our academic expert!
Similar Questions
An ideal refrigerator has a freezer at a temperature of
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests