The temperature of the two outer surfaces of a composite slab consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively are T₂ and T₁(T₂ >T₁). The rate of heat transfer through the slab, in steady state is
$[\frac{KA (T_{2} - T_{1})}{X}] f$ with f equal to

Question

Infinity Learn · Accepted Answer

The two plates arc connected in series. Their total thermal resistance is given by $$RS=R1+R2=XKA+4X2KA=3XKAThe$$ rate of flow of heat through the composite plate is given by  $$Qt=$$Δθ$$RS=T2$$−$$T1(3x/KA)=KAT2$$−$$T13x$$                                     $$=KAT2$$−$$T1x$$×$$13Comparing$$ with given equation, we get  $$f=13$$.

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The temperature of the two outer surfaces of a composite slab consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively are T2 and T1(T2 >T1). The rate of heat transfer through the slab, in steady state is KAT2−T1Xf with f equal to

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