The temperature of the two outer surfaces of a composite slab, consists of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x respectively are T2 and T1(T2>T1). The rate of heat transfer through slab, in a steady state is AT2−T1KXf , with f equals to
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a
1
b
½
c
2/3
d
1/3
answer is D.
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Detailed Solution
Req=xKA+4x2KA=3xKAQt=T2−T1Req=T2−T1KA3xCompare this equation with given equation