The temperature of a wire is doubled. The Young's modulus of elasticity
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a
will also double
b
will become four times
c
will remain same
d
will decrease
answer is D.
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Detailed Solution
We know that, with increase in temperature, length of a wire changes as Lt=L0(1+αΔT)where, ΔT is change in the temperature, L is original length, α is coefficient of linear expansion and Lt is length at temperature T. Now, we can write, ΔL=Lt−L∘=L∘αΔT, Young's modulus (Y)= Stress Strain =FL∘A×ΔL=FL∘AL∘αΔT∝1ΔTAs, Y∝1ΔTWhen temperature (ΔT) increases, Y decreases.