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Q.

The temperatures across two different slabs A and B are shown in the steady state (as shown in figure).The ratio of thermal conductivities of A and B is

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a

2:3

b

3:2

c

1:1

d

5:3

answer is B.

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Detailed Solution

dQdt×1A=KA(50−30)3 (for slab A)=KB(50−20)3 (for slab B) 2KA=3KBor, KA/KB=3/2

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