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The temperatures across two different slabs A and B are shown in the steady state (as shown in figure).The ratio of thermal conductivities of A and B is
detailed solution
Correct option is B
dQdt×1A=KA(50−30)3 (for slab A)=KB(50−20)3 (for slab B) 2KA=3KBor, KA/KB=3/2Talk to our academic expert!
Similar Questions
Two rods of length and and coefficients of thermal conductivities and are kept touching each other. Both have the same area of cross-section. The equivalent of thermal conductivity is
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