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Q.

The temperatures of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively are T2 and T1 (T2 > T1). The rate of heat transfer through the slab, in a steady state is 1fAT2−T1Kx, where f is equal to ____________

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answer is 3.

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Detailed Solution

Equation of thermal conductivity of the given combination Keq=l1+l2l1K1+l2K2=x+4xxK+4x2K=53KHence, rate of flow of heat through the given combination isQt=Keq⋅AT2−T1(x+4x)=53KAT2−T15x=13KAT2−T1xOn comparing it with given equation, we get f=3
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