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Questions  

The tension of a stretched string is increased by 69%. In order to keep its frequency of vibration constant, its length must be increased by 

a
20%
b
30%
c
69%
d
69%

detailed solution

Correct option is B

n∝Tl⇒l∝T             (As n = constant)⇒l2l1=T2T1=l1169100⇒l2=1.3l1=l1+30%  of  l1

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A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)


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