The tension in a string holding a solid block below the surface of a liquid (where dliquid>dblock) as in shown in the figure is T when the system is at rest. Then what will be the tension in the string if the system has upward acceleration a?

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T1−ag

T1+ag

Tag−1

agT

answer is B.

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Detailed Solution

here buoyant force is greater than weight of the block T=vdlg−vdsgWhen it moves up with acceleration ‘a’.T'=vdl−vdsg+a=vdl−vdsg1+ag=T1+ag

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