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Q.

At a termperature T K, the pressure of 4.0 g argon in a bulb is p. the bulb is put in a bath having temperature higher by 50 K than the first one. 0.8 g of argon gas had to be removed to maintained original pressure. The temperature T is equal to

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a

510 K

b

200 K

c

100 K

d

73 K

answer is B.

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Detailed Solution

PV=4MAr.RT _______________(1) Now, PV=(4−.8)MArR(t+50) _____(2)(1)&(2)⇒(4−.8)(T+50)=4T 4T−.8T+200−.8×50=4T T=200−.8×50.8 T=200K
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